The Nth Term Of A Geometric Sequence Is 4/3.If The First Term Is 1/48 And The Common Ratio Is 2, What Is N?

the nth term of a geometric sequence is 4/3.if the first term is 1/48 and the common ratio is 2, what is n?

 

an=4/3

a1=1/48

r=2

Formula:

an=a1(r)^(n-1)

4/3=(1/48)(2)^(n-1)

1/48(2)^(n-1)=4/3

Divide Both side by 1/48

2^(n-1)=64

log(2)^(n-1)=log(64)

n-1=((log)(64))/((log)(2))

n-1=6

n=7